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cosX的6次方+sinX的6次方 求周期?
人气:167 ℃ 时间:2019-10-03 08:37:31
解答
sin(x)^6+cos(x)^6=【sin(x)^2+cos(x)^2】*【sin(x)^4-sin(x)^2*cos(x)^2+cos(x)^4】=sin(x)^4+2*sin(x)^2*cos(x)^2+cos(x)^4-3*sin(x)^2*cos(x)^2=【sin(x)^2+cos(x)^2】^2-3*sin(x)^2*cos(x)^2=1-3*sin(x)^2*co...
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