已知f(x)是定义在「-3,3」的偶函数,在「0,3」上单调递增,解不等式f(2x-1)>f(x)
人气：276 ℃ 时间：2019-10-19 21:41:10
解答
f(x)=f(-x)
所以f(x)=f(|x|)
x>=0递增
所以f(|2x-1|)>f(|x|)
所以3>=|2x-1|)>|x|
3>=|2x-1|
-3
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