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等差数列{an}a4+a6+a8+a10+a12=120.则a9-1/3a11的值为
人气:475 ℃ 时间:2020-04-11 02:56:15
解答
a4+a6+a8+a10+a12=120
5a8=120
a8=24
a9-1/3*a11
=a8+d-1/3*(a8+3d)
=a8+d-1/3a8+d
=a8+1/3a8
=24+1/3*24
=24+8
=32
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