复数方程Z³-3iZ-(3-i)=0可化为Z³+i-3iZ-3=0
也就是Z³-i³-3i(z+1/i)=0
即(z-i)(z²+iz+i²)-3i(z-i)=0
所以(z-i)(z²+iz-1-3i)=0
所以z=i