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化简求值.2/(a-1)+(a²-4a+4)/(a²-1)÷(a-2)/(a+1).其中a=1+根号2
括号里的是分子和分母
人气:410 ℃ 时间:2019-11-05 04:16:23
解答
2/(a-1)+(a²-4a+4)/(a²-1)÷(a-2)/(a+1).
=2/(a-1)+(a-2)²/(a+1)(a-1)×(a+1)/(a-2)
=2/(a-1)+(a-2)/(a-1)
=a/(a-1)
当a=1+√2时
原式=(1+√2)/√2
=(2+√2)/2
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