(1)
令x=0
则f(y)=2f(y)-y²-3y
f(y)=y²+3y
令y=x
则f(x)=x²+3x
(2)方法2
令y=0
则f(x)=2f(0)+x²+3x
令x=y=0,则f(0)=2f(0)=0
f(x)=x²+3x