∵(cosy)dy/dx-siny=0
==>(cosy)dy=sinydx
==>(cosy)dy/siny=dx
==>d(siny)/siny=dx
==>ln│siny│=x+ln│C│ (C是积分常数)
==>siny=Ce^x
∴原方程的通解是siny=Ce^x.帮忙看一下好吗求下列微分方程的通解y'+cosx=e^(-sinx)