由题得：f(x)=(√3/2)sin2x-(1/2)cos2x-1=sin(2x-π/6)-1
所以,当2x-π/6=2kπ-π/2 时,(k∈Z)
即：当,x=kπ-π/6 时,(k∈Z)
f(x)有最小值=-2,最小正周期=2π/2=π