如图,d.e是△abc的边bc上两点,且ab=ac,ae=ad,试说明∠BAD=∠CAE
人气:451 ℃ 时间:2020-02-18 20:23:38
解答
ab=ac,则∠ABC=∠ACB;
ae=ad,则∠ADE=∠AED,且∠ADB=180-∠ADE,∠AEC=180-∠AED;
则∠ADB=∠AEC;
△ABD与△ACE相似,∠BAD=∠CAE
推荐
- 已知:如图,点D、E在△ABC的边BC上,AD=AE,∠BAD=∠CAE.求证:AB=AC
- 如图,∠BAD=∠CAE,AB=AD,AC=AE,说明△ABC≌△ADE的理由.
- 如图,在△ABD和△ACE中,AB=AD,AC=AE,∠BAD=∠CAE,连接BC、DE相交于点F,BC与AD相交于点G.求证:BC=DE.
- 如图,已知AB/AD=BC/DE=AC/AE,求证:△ABD∽△ACE.
- 如图,AB=AC,AB的垂直平分线交AC于D点,若AD=BC,∠ABC=72°,点E在BC的延长线上,且CE=CD连AE,求∠CAE
- 铁岭的由来
- 否定疑问句一定表示已知答案的刻意反问吗,
- 4个连续奇数的连乘积是326025,它们的和是_.
猜你喜欢