...题目写的有点不习惯.裂项相消原式=99-[1/（1*2）+1/(2*3)+...+1/(99*100)]=99-[(2-1)/(1*2)+(3-2)/(2*3)+...+(100-99)/(99*100)]=99-[1/1-1/2+1/2-1/3+...+1/99-1/100]=99-(1-0.01)=98.01