∵正方形ABCD和AEFG，∴AG=AE，AD=AB，∠DAB=∠GAE=90°，∴∠DAG=∠EAB，∴△ADG≌△ABE，∴DG=BE，∵正方形ABCD和AEFG，∴∠DAC=∠GAF=12×90°=45°，∴∠DAG=∠FAC=∠EAB，由勾股定理得：AFAG=ACAD=2，∴△ABE∽...