定积分数学题
x/(1+x^2)^1/2在[0,2]的定积分.
人气:357 ℃ 时间:2020-02-05 09:58:47
解答
楼上正解,但可以不用设t
为了方便,上下限不写,最后带
原式= 1/2∫1/√(1+x^2) d(1+x^2)
=1/2 * {2√(1+x^2)}
=√(1+x^2)|
代入上下限0,2得:
=√5-1
应该知道√是根号的意思吧,
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