求函数f(x)=log‹a›(3x²-2x-1)(a>0,a≠1)的单调区间f(x)=log‹a›(3x²-2x-1)【定义域：(-∞,-1/3)∪(1,+∞)】f′(x)=(6x-2)/[(3x²-2x-1)lna]=6(x-1/3)/[3(x+1/3)(x-1)lna]=2(x-...