T1=a1=1-a1 2a1=1 a1=1/2a1a2...an=Tn=1-an (1)a1a2...a(n-1)=Tn-1=1-a(n-1) (2)(1)/(2)an=(1-an)/[1-a(n-1)]整理,得[2-a(n-1)]an=1an=1/[2-a(n-1)]a2=1/(2-1/2)=2/3假设当n=k(k∈N+,且k≥2)时,ak=k/(k+1),则当n=k+1...