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把关于X的方程x²-x+1/x-1=a=1/a-1变形为方程x+1/x=c+1/c的形式是?方程的解是?
已知答案是(x-1)+1/x-1=a-1+1/a-1,解是x1=a,x2=a/a-1 Q啊题目打错了是x²-x+1/x-1=a+1/a-1变形
人气:457 ℃ 时间:2019-11-09 20:33:02
解答
(x²-x)/(x-1)+1/(x-1)=a+1/(a-1)
x+1/(x-1)=a+1/(a-1)
两边减去1
(x-1)+1/(x-1)=(a-1)+1/(a-1)
这样吧x-1和a-1看做整体即可����(x²-x)/(x-1)+1/(x-1)��һ������ô�ó����ģ����з�������ν�����ģ�(a+b/c=a/c+b/ca+1/(a-1)����ô�ó����أ�Ϊʲô���߶�Ҫ��һ��分母是a-1所以a也要变成a-1行了,采纳吧
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