已知函数f(x)=x^3-3ax^2+3x+1 设f(x)在区间(2,3)中至少有一个极值点,求a的范围.
已知函数f(x)=x^3-3ax^2+3x+1
设f(x)在区间(2,3)中至少有一个极值点,求a的范围.
人气:154 ℃ 时间:2019-08-18 09:47:11
解答
f'(x)=3x^2-6ax+3,为使f(x)在(2,3)内至少有一极值点,则f'(x)在此间内有零点,且△>=0
综上有:f'(2)*f'(3)=0
整理有5/4
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