dy/dx=（x+y）/（x-y）,求y=f（x）.
人气：458 ℃ 时间：2019-11-13 00:54:57
解答
dy/dx=(x+y)/(x-y),dy/dx=(1+y/x)/(1-y/x)u=y/x,dy/dx=u+xdu/dx(1+u)/(1-u)=u+xdu/dxdx/x=(1-u)du/(1+u^2)ln|x|=arctanu-(1/2)ln|1+u^2|+C(1/2)ln|x^2+y^2|-arctan(y/x)=C
推荐
- 证明 ∫[0,a]dx∫[0,x]f(y)dy=∫[0,a](a-x)f(x)dx
- y=f（x^2+1）,且f'（x）=x^2,则dy／dx | x=-1=?
- dy/dx=e^（x^2）、求y=f（x）
- ∫[0,1] dx∫[0,x]f(x,y)dy= ?
- 设f(x)=1/x,y=f[(x-1)/(x+1)],求dy/dx
- 坚持这项工作由一个有经验的工人做She insisted that this work should be done by an exp
- Liu Tao can put some bookson his head.改否定句
- "心灵岛上的灯塔"含义是什么?
猜你喜欢
