(a/(b+2c+3d))+(b/(c+2d+3a))+(c/d+2a+3b))+(d/(a+2b+3c))>=2/3 不等式证明
人气：473 ℃ 时间：2019-10-11 17:35:48
解答
b+2c+3d=t-----b=t-2c-3dc+2d+3a=z -----c=z-2d-3ad+2a+3b=m ------d=m-2a-3ba+2b+3c=n d+2a+3b=d+2a+3t-6c-9d=2a+3t-6c-8d=mc+2d+3a=a+2t-4c-3d+3c=a+2t-c-3d=a+2t-z+2d+3a-3d=4a+2t-z-d=6a+2t-z-m+3b=n6a+3b=z+m+n...
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