已知函数f(x)=1/3x^3-1/2(a+1)x^2+ax 则f’(x)=x^2-(a+1)x+a=(x-1)(x-a)1,设a＞0切a＜1则函数f(x)在,x≥0 中最小值为f(0)或f(1)则f(0)>-2/3a f(1)>-2/3a 则o＜a＜12.设a≥1 则f（x)的最小值为f(0)或f(a) 则f(0)>-2/3...