辅助线：延长CB到G,使BG=DQ∵正方形ABCD,AB=AD,AB⊥BC,AD⊥DC∴△ABG全等于△ADQ∴∠GAB=∠QAD,∠AGB=∠AQD∵AQ平分角PAD∴∠GAB=∠QAP∵AB‖CD∴∠AQD=∠QAB∴∠GAB =∠QAB=∠GAP∴△APG为等腰△,AE=PG=BP+BG=BP+DQ...