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函数y=-2sin(π/3-x)的单调区间是
人气:388 ℃ 时间:2020-06-23 22:09:16
解答
y=-2sin(π/3-x)=2sin(x-π/3)
所以 2kπ-π/2<=x-π/3<=2kπ+π/2(k是任意整数)时y递增
2kπ+π/2<=x-π/3<=2kπ+3π/2(k是任意整数)时y递减
所以2kπ-π/6<=x<=2kπ+5π/6(k是任意整数)时y递增
2kπ+5π/6<=x<=2kπ+11π/6(k是任意整数)时y递减
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