已知,xyz=0,求x/(xy+x+1)+y/(yz+y+1)+z/(xz+z+1)值?
人气:243 ℃ 时间:2019-09-22 09:35:09
解答
同学,xyz=1吧?这样的话,原式=x/(xy+x+xyz)+y/(yz+y+xyz)+z/(xz+z+xyz)=1/(y+1+yz)+1/(z+1+xz)+1/(x+1+xy)=xyz/(y+xyz+yz)+1/(z+1+xz)+1/(x+1+xy)=xz/(1+xz+z)+1/(z+1+xz)+1/(x+1+xy)=(xz+1)/(z+1+xz)+1/(x+1+xy)=(...
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