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判断函数f(x)= [根号下(1+x^2+x-1) ]/ ( (1+x^2+x+1)) 的的奇偶性
人气:102 ℃ 时间:2019-08-20 18:38:40
解答
先判断当x=0时,f(x)是否为0,若不为0,则不是奇函数(可用在选择题排除法上),再按常规判断其奇偶性. 第一步:f(0)=0第二步:f(x)=[(1+x^2)^(1/2)+x-1]/[(1+x^2)^(1/2)+x+1]=[(1+x^2)^(1/2)+x-1]*[(1+x^2)^(1/2)-x-1...
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