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已知方程sin(2x+π/3)-1=a,x∈[-π/6,13π/12]有两解,求a的取值范围
人气:155 ℃ 时间:2019-08-21 13:25:46
解答
∵-π/6≤x≤13π/12
∴0≤2x+π/3≤5π/2
sin(2x+π/3)=a+1
令t=2x+π/3∈[0,5π/2] sint=a+1 (画出sint在[0,5π/2]的函数图像)
a+1 =1 或 -1≤a+1
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