已知数列{an}满足a1=1,an+1·an=2^n 则s2012
人气:454 ℃ 时间:2020-04-16 11:06:33
解答
我来帮你解答吧!O(∩_∩)O~ 由an+1·an=2^n,可得an+2·an+1=2^(n+1),两者相除,可得an+2/an=2,观察此式,可以发现,数列{an}的奇数项和偶数项分别成等比数列,又a1=1,an+1·an=2^n,可以求出a2=2,则 数列{an}...
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