令x = secz,dx = secztanz dzx > 1,z ∈[0,π/2),√(x² - 1) = √(sec²z - 1) = tanz∫(1~2) √(x² - 1)/x dx= ∫(0~π/3) tanz/secz * secztanz dz= ∫(0~π/3) tan²z dz= ∫(0~π/3) (sec...