∫(0,2) x√(2x - x²) dx= ∫(0,2) x√[- (x² - 2x + 1) + 1] dx= ∫(0,2) x√[1 - (x - 1)²] dx令x - 1 = sinθ,dx = cosθ dθx = 0 --> θ = - π/2x = 2 --> θ = π/2= ∫(- π/2,π/2) (1 + si...