解a=(sinx,cosx)b=(1,√3)∴a-b=(sinx-1,cosx-√3)∴/a-b/=√(sinx-1)²+(cosx-√3)²=√sin²x-2sinx+1+cos²x-2√3cosx+3=√5-2sinx-2√3cosx=√5-(2sinx+2√3cosx)=√5-4sin(x+π/3)∵-1≤sin(x+...