已知双曲线y=3/x和直线y=kx+2相交于点A(X1,Y1)和点B(X2,Y2),且X1*X1+X2*X2=10,求k的值?
人气:362 ℃ 时间:2020-05-10 02:20:15
解答
y=3/x,y=kx+2
(kx+2)x=3
kx^2+2x-3=0
x1+x2=-2/k,x1x2=-3/k
X1*X1+X2*X2=10
(x1+x2)^2-2x1x2=10
4/k^2+6/k=10
5k^2-3k-2=0
k=-2/5,或k=3
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