已知(1+tanx)/(1-tanx) =3+2根号2 ,求(sin^2 x+根号2sinx*cosx-cos^2 x)/(sin^2 x+2cos^2 x) 的值
人气:285 ℃ 时间:2019-08-21 18:45:17
解答
(1+tanx)/(1-tanx) =3+2根号2 ,
解得tanx=√2/2.
(sin^2 x+根号2sinx*cosx-cos^2 x)/(sin^2 x+2cos^2 x)
=(tan^2x+√2tanx-1)/(tan^2x+2)
=(1/2+1-1)/(1/2+2)
=1/5.
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