一百克某硫酸铜溶液恰好与五点六克铁完全反应 1:求生成铜的质量 2:反应后所得溶液的质量分数
人气:291 ℃ 时间:2020-05-17 15:14:46
解答
CuSO4+Fe=FeSO4+Cu
56 152 64
5.6g x y
56/5.6g=152/x=64/y
x=15.2g y=6.4g
1:生成铜的质量 6.4g
2:反应后所得溶液的质量分数 15.2g/(100g+5.6g-6.4g)*100%=15.3%
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