> 数学 >
数学三角函数 函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.
怎么把 函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.拆开,再结合,
人气:336 ℃ 时间:2020-09-19 01:54:29
解答
f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1=sin2x+2sin(x+π/4)sin(sin[π/2+( x+π/4)]+1=sin2x+2sin(x+π/4)cos( x+π/4)+1=sin2x+sin(2x+π/2)+1=sin2x+cos2x+1=√2sin(2x+π/4) +1
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版