数学三角函数 函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.
怎么把 函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.拆开,再结合,
人气:336 ℃ 时间:2020-09-19 01:54:29
解答
f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1=sin2x+2sin(x+π/4)sin(sin[π/2+( x+π/4)]+1=sin2x+2sin(x+π/4)cos( x+π/4)+1=sin2x+sin(2x+π/2)+1=sin2x+cos2x+1=√2sin(2x+π/4) +1
推荐
- 数学三角函数 函数f(x)=2sinxcosx+2sin(x+π/4)sin(x+3π/4)+1.
- f(x)=2sin²x-λcosx+5
- f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+/4π) 三角函数
- 求三角函数函数y=1-2sin^x+2cosx值域
- 三角函数 已知f(x)=根号2/2sin(2x+π/4)+1/2,当x∈[-π/8,3π/8]时,求f(x)的单调区间
- 1选A,2选B,我不确定答案,
- Would you like to fly a kite with me?Sorry,I h_______ ever have time for a game
- 取三支干净的小试管,试管A盛有开始蒸馏出的液体,试管B装有蒸馏一段时间后收集的,试管C放入没蒸馏的硬水
猜你喜欢