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把x的五次方减一分解因式
要有具体过程和结果.谢谢
人气:305 ℃ 时间:2019-10-10 14:37:53
解答
x^5-1
=x^5-x+(x-1)
=x(x^4-1)+(x-1)
=x(x^2+1)(x^2-1)+(x-1)
=x(x^2+1)(x+1)(x-1)+(x-1)
=(x-1)[x(x^2+1)(x+1)+1)
=(x-1)(x^4+x^3+x^2+x+1)
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