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已知x^2y+2xy+3=-18 求dy/dx
人气:475 ℃ 时间:2020-02-05 20:25:44
解答
x²y+2xy+3=-18
两边同时对x求导得:
2xy+x²dy/dx+2y+2xdy/dx+0=0
2xy+2y+(x²+2x)dy/dx=0
(x²+2x)dy/dx=-(2xy+2y)
dy/dx=-(2xy+2y)/(x²+2x)2xy+x²dy/dx+2y+2xdy/dx+0=0 这一部不太理解~x²y对x求导为2xy+x²dy/dx2xy对x求导为2y+2xdy/dxsorry我打错了是2xy^32xy³对x求导为2y³+6xy²dy/dx请采纳。x^2y求导不应该是2xydy/dx+x^2dy/dx不是的,x²y对x求导是(x²)'y+x²y '=2xy+x²y '=2xy+x²dy/dx
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