解:a²-3a+1=0,则a不为0.方程两边同除以a,得:a-3+1/a=0,a+1/a=3.∴(a+1/a)²=9,a²+1/a²+2=9,a²+1/a²=7.故a²/(a⁴+a²+1)=1/(a²+1+1/a²) ----------(即...