β=3k2π/2=9k2π/6,k2∈Z.
α =5k1π/3=10k1π/6,|k1|≤10,k1∈Z.
α =β时,10k1π/6=9k2π/6,k1=9k2/10,k2∈Z.
所以k2=-10,0,10时,k1=-9,0,9.
此时α =-15π,0,15π.
-15π与15π的终边都与π的终边相同,
A∩B={θ|θ= 2kπ+π或2kπ+0,k∈Z }
={θ|θ= kπ,k∈Z }