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关于正弦定理的一道题
在三角形ABC中,求证:a/sinA=(b+c)/(sinB+sinC)
人气:100 ℃ 时间:2020-01-25 17:59:51
解答
a/sinA=(b+c)/(sinB+sinC)正弦定理:a/sinA=b/sinB=c/sinC设a/sinA=b/sinB=c/sinC=k则b=sinB*k,c=sinC*k(b+c)/(sinB+sinC)=(sinB*k+sinC*k)/(sinB+sinC)=k(sinB+sinC)/(sinB+sinC)=k则a/sinA=(b+c)/(sinB+sinC)=k由...
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