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已知关于x的方程sinx-1/sinx+1=m有实数解,求m的取值范围》?
人气:468 ℃ 时间:2020-01-28 13:52:37
解答
sinx-1=msinx+msinx=(m+1)/(1-m)-1<=sinx<=1分母不等于0-102/(1-m)>01-m>0m<1(m+1)/(1-m)<=1(m+1)/(1-m)-1<=02m/(1-m)<=02m(1-m)<=0m(m-1)>=0m<=0,m>=1所以m<=0
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