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B(1,1/2),(1,1/3),x与y相互独立.求p{x=1,y=1},求计算方法
人气:204 ℃ 时间:2020-07-18 07:21:46
解答
p{x=1,y=1}=p{x=1)*(y=1}
=c(3,1)*(1/2)^1*(1/2)^(3-1)*c(1,1)*(1/3)^1*(1/3)^(1-1)
=1/8但是答案是1/6p{x=1,y=1}=p{x=1)*(y=1}
=c(1,1)*(1/2)^1*(1/2)^(1-1)*c(1,1)*(1/3)^1*(1/3)^(1-1)
=1/6
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