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设sinθ+cosθ=1/2 求sin2θ
人气:369 ℃ 时间:2020-06-02 07:10:38
解答
已知:sinθ + cosθ = 1/2
则:(sinθ + cosθ)^2 = (sinθ)^2 + (cosθ)^2 + 2sinθcosθ =[(sinθ)^2 + (cosθ)^2] + 2sinθcosθ
= 1 + 2sinθcosθ
= 1 + sin(2θ)
= 1/4
即:sin(2θ) = 1/4 - 1 = -3/4
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