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∫(4x+3)/(x-2)^3dx
求不定积分
人气:390 ℃ 时间:2020-06-27 20:29:06
解答
∫(4x+3)/(x-2)^3dx=∫(4x-8+11)/(x-2)^3dx=∫(4x-8)/(x-2)^3dx+∫11/(x-2)^3dx=4∫1/(x-2)^2dx+11∫1/(x-2)^3dx=-4/(x-2)-11/2(x-2)^2+C=-((8x-5)/2(x-2)^2)+C(C为积分常数).
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