∫(4x+3)/(x-2)^3dx求有理函数积分?_数学解答

∫(4x+3)/(x-2)^3dx求有理函数积分?

人气：155 ℃　时间：2020-06-17 00:31:47

解答

∫(4x+3)/(x-2)^3dx=∫(4x-8+11)/(x-2)^3dx=∫(4x-8)/(x-2)^3dx+∫11/(x-2)^3dx
=∫4/(x-2)^2dx+∫11/(x-2)^3dx
=-4/(x-2)-11/2(x-2)^2 +C