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Sn=(2^2)/(1×3)+(4^2)/(3×5)+.((2n)^2)/(2n-1)(2n+1)
人气:412 ℃ 时间:2020-08-27 07:08:24
解答
Sn=(2^2)/(1×3)+(4^2)/(3×5)+.((2n)^2)/(2n-1)(2n+1)=(1+1/(1*3))+(1+1/(3*5))+.(1+1/(2n-1)(2n+1))=n+(1/1*3+1/3*5+.1/(2n-1)(2n+1))=n+(1/2)(1-1/(2n+1))=n+n/(2n+1)=(2n^2+2n)/(2n+1)
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