已知f(x)=lnx+(1/x)(x>0),g(x)=lnx-x(x>0)求证当x>0时,xln(1+1/x)<1<(x+1)ln(1+1/x）
人气：337 ℃ 时间：2020-06-04 01:46:22
解答
只需证明x>0时 1/(x+1)g(0)=0
所以ln(1+t)>t/(1+t) 1/x>0 则ln(1+1/x)>x/1+x
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