题目有误差
2^1001+3^1002+(1/6)^1003≈2^1001+3^1002
如果是这样,算出来的数巨大无比
2^1001*3^1002*(1/6)^1003
=[2^1001*(1/2)^1001]*[3^1002*(1/3)^1002]*(1/2)^2*(1/3)
=1*1*(1/4)*(1/3)
=1/12
如果是这样,还可以算算