f（x）=(sinx)^2+2√3sin（x+π/4）cos(x-π/4)-(cosx)^2-√3=2√3[sin(x+π/4)]^2-cos2x-√3=√3[1-cos(2x+π/2)]-cos2x-√3=√3sin2x-cos2x=2sin(2x-π/6),(1)f(x)的最小正周期=π.递减区间由（2k+1/2)π...