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对1/(4x^2)(1+4x^2)微积分,
人气:354 ℃ 时间:2020-09-28 23:24:57
解答
微分:d/dx 1/[(4x²)(1 + 4x²)] = d/dx 1/(16x⁴ + 4x²)= - (16x⁴ + 4x²)'/(16x⁴ + 4x²)²= - (16 * 4x³ + 4 * 2x)/[(4x²)²(1 + 4x²)²]= -...
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