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tana=-22,sin^a-3sinacosa+1=?
人气:119 ℃ 时间:2020-04-10 16:49:34
解答
tana=-22
则(seca)^2=1+(tana)^2=485
(cosa)^2=1/(seca)^2=1/485
(sina)^2-3sinacosa+1
=(cosa)^2[(tana)^2-3tana+(seca)^2]
=(1/485)*(484+66+485)
=1035/485
=207/97
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