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y=sin^x+根号3sinx*cosx的最小正周期和单调区间
人气:417 ℃ 时间:2020-04-28 10:04:00
解答
y = sin²x + √3sinxcosx
= (1 - cos2x)/2 + (√3/2)sin2x
= (√3/2)sin2x - (1/2)cos2x + 1/2
= sin(2x - π/6) + 1/2
蕞小正周期:2π/2 = π
2kπ - π/2 < 2x - π/6 < 2kπ + π/2
kπ - π/6 < x < kπ + π/3
单增区间:(kπ - π/6,kπ + π/3),k∈Z
2kπ + π/2 < 2x - π/6 < 2kπ + 3π/2
kπ + π/3 < x < kπ + 5π/6
单减区间:(kπ + π/3,kπ + 5π/6),k∈Z
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