f(x)=sinx^2+根号3*sinxcosx化简_数学解答

f(x)=sinx^2+根号3*sinxcosx化简

人气：128 ℃　时间：2019-11-04 09:29:26

解答

f(x)=sinx^2+√3*sinxcosx
=(1-cos2x)/2+(√3/2)sin2x
=1/2-[(1/2)*cos2x-(√3/2)sin2x]
=1/2-[sinπ/6*cos2x-cosπ/6sin2x]
=1/2-sin(π/6-2x)
=1/2+sin(2x-π/6)